Answer
$\tan \left(\frac{1}{1+s^{2}}\right) .$
Work Step by Step
By making use of Theorem 1 (FTC II), we have
$$
\frac{d}{d s} \int_{-2}^{s} \tan \left(\frac{1}{1+u^{2}}\right) d u=\tan \left(\frac{1}{1+s^{2}}\right) .
$$
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