Answer
$f(x)
= \frac{x^4}{2}-\frac{1}{2}.$
Work Step by Step
We have
$$f(x)=\int_{1}^{x^2}t \ dt =\frac{1}{2}t^2 |_{1}^{x^2}\\
= \frac{x^4}{2}-\frac{1}{2}.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 13
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