Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 15


$$f(x)=\frac{1}{4}(x^6-81x^2) .$$

Work Step by Step

We have $$f(x)=\int_{3\sqrt x}^{x^{3/2}} t^3dt=\frac{1}{4} t^4|_{3\sqrt x}^{x^{3/2}}\\ = \frac{1}{4}(x^6-81x^2) . $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.