Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 14


$f(x) = \tan( x/4) -\tan (x/2) .$

Work Step by Step

We have $$f(x)=\int_{x/2}^{x/4}\sec^2u\ du=\tan u |_{x/2}^{x/4}\\ = \tan( x/4) -\tan (x/2) . $$
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