Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 42



Work Step by Step

We have $$ \int_{-x}^x(t^3+t)dt=\frac{1}{4}t^4+\frac{1}{2}t^2|_{-x}^x\\ =\frac{1}{4}x^4+\frac{1}{2}x^2-\frac{1}{4}x^4-\frac{1}{2}x^2\\ =0. $$
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