Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 16



Work Step by Step

We have $$\int_{4}^{1} t^{5/2}dt=\frac{1}{7/2}t^{7/2}|_{4}^1=\frac{2}{7} -\frac{2}{7} 4^{7/2}\\=\frac{2}{7} -\frac{2^8}{7} =-\frac{254}{7}.$$
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