Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 37



Work Step by Step

We have $$ \int_{0}^{\pi}|\cos x| d x= \int_{0}^{\pi/2}|\cos x| d x+\int_{\pi/2}^{\pi}|\cos x| d x\\ =\int_{0}^{\pi/2}\cos xd x-\int_{\pi/2}^{\pi}\cos x d x\\ =\sin x|_{0}^{\pi/2}-\sin x|_{\pi/2}^{\pi}\\ =1-(-1)=2 . $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.