Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 17


$$\frac{2}{3} .$$

Work Step by Step

We have $$\int_{1}^{3} t^{-2}dt=\frac{1}{-1}t^{-1}|_{1}^3=-\frac{1}{3} +1=\frac{2}{3} .$$
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