Answer
$$\frac{11}{6}.$$
Work Step by Step
We have
$$\int_{1}^{2}\left(x^2-x^{-2}\right) d x=\frac{x^{3}}{3}+x^{-1}|_{1}^2\\
=\frac{8}{3}+\frac{1}{2}-\frac{1}{3}-1=\frac{11}{6}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 258: 21
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