Answer
$\frac{35}{3}$
Work Step by Step
$\int^{2}_{-3}u^{2}du= [\frac{u^{3}}{3}]^{2}_{-3}= \frac{2^{3}}{3}-\frac{-3^{3}}{3}=\frac{35}{3}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 8
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