Answer
$$\frac{8}{3}.$$
Work Step by Step
We have
$$\int_{-1}^{1}\left(5u^4+u^2-u\right) d u=\frac{5u^{5}}{5}+\frac{u^3}{3}-\frac{u^2}{2}|_{-1}^1\\
=\frac{5}{5}+\frac{1}{3}-\frac{1}{2}+\frac{5 }{5}+\frac{1}{3}+\frac{1}{2}=\frac{8}{3}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 12
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