Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 12



Work Step by Step

We have $$\int_{-1}^{1}\left(5u^4+u^2-u\right) d u=\frac{5u^{5}}{5}+\frac{u^3}{3}-\frac{u^2}{2}|_{-1}^1\\ =\frac{5}{5}+\frac{1}{3}-\frac{1}{2}+\frac{5 }{5}+\frac{1}{3}+\frac{1}{2}=\frac{8}{3}.$$
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