Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 13



Work Step by Step

We have $$\int_{0}^{4} \sqrt y dy=\frac{1}{3/2}y^{3/2}|_{0}^4=\frac{2}{3}4^{3/2}=\frac{16}{3}.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.