Answer
$$\frac{16}{3}.$$
Work Step by Step
We have
$$\int_{0}^{4} \sqrt y dy=\frac{1}{3/2}y^{3/2}|_{0}^4=\frac{2}{3}4^{3/2}=\frac{16}{3}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 13
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