Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 7



Work Step by Step

We have $$\int_{0}^{1}\left(4 x-9 x^{2}\right) d x=\frac{4x^2}{2}-\frac{9x^3}{3}|_0^1\\ =2-3=-1.$$
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