# Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 10

$0$

#### Work Step by Step

We have $$\int_{-2}^{2}\left(10x^9+3x^5\right) d x=\frac{10x^{10}}{10}+\frac{3x^6}{6}|_{-2}^2\\ =2^{10}+2^5-2^{10}-2^5=0.$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.