Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 10



Work Step by Step

We have $$\int_{-2}^{2}\left(10x^9+3x^5\right) d x=\frac{10x^{10}}{10}+\frac{3x^6}{6}|_{-2}^2\\ =2^{10}+2^5-2^{10}-2^5=0.$$
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