Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 58



Work Step by Step

$\int^{1}_{0}f(x)dx+\int^{4}_{1}f(x)dx=\int^{2}_{0}f(x)dx+\int^{4}_{2}f(x)dx $ $\implies \int^{4}_{2}f(x)dx=\int^{1}_{0}f(x)dx+\int^{4}_{1}f(x)dx-\int^{2}_{0}f(x)dx $ $=1+7-4=4$
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