Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 53

Answer

$7$

Work Step by Step

We have $$ \int_{0}^{1}\left(12 x^{3}+24x^2-8x\right) d x\\ =12\frac{(1^4)}{4}+24\frac{(1^3)}{3}-8\frac{(1^2)}{2}=7. $$
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