Answer
3
Work Step by Step
$\int^{2}_{0}f(x)dx= \int^{1}_{0}f(x)dx+\int^{2}_{1}f(x)dx$
$⇒\int^{2}_{1}f(x)dx= \int^{2}_{0}f(x)dx-\int^{1}_{0}f(x)dx$$=4-1=3$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 56
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