Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 56



Work Step by Step

$\int^{2}_{0}f(x)dx= \int^{1}_{0}f(x)dx+\int^{2}_{1}f(x)dx$ $⇒\int^{2}_{1}f(x)dx= \int^{2}_{0}f(x)dx-\int^{1}_{0}f(x)dx$$=4-1=3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.