Answer
$-\frac{63}{4}$
Work Step by Step
$\int^{3}_{0}(x-x^{3})dx=\int^{3}_{0}xdx-\int^{3}_{0}x^{3}dx $
$=\frac{x^{2}}{2}|^{3}_{0}-\frac{x^{4}}{4}|^{3}_{0}=\frac{3^{2}}{2}-\frac{3^{4}}{4}$
$=\frac{9}{2}-\frac{81}{4}=-\frac{63}{4}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 51
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