Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 8


$ v' = 10T^{-1/2}$

Work Step by Step

We know that $ v = 20\sqrt{T} = 20T^{1/2}$. To find the rate of change, we have to find the derivative of both sides with respect to T using the power rule: $ v' = 10T^{-1/2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.