# Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 8

$v' = 10T^{-1/2}$

#### Work Step by Step

We know that $v = 20\sqrt{T} = 20T^{1/2}$. To find the rate of change, we have to find the derivative of both sides with respect to T using the power rule: $v' = 10T^{-1/2}$

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