Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 8

Answer

$ v' = 10T^{-1/2}$

Work Step by Step

We know that $ v = 20\sqrt{T} = 20T^{1/2}$. To find the rate of change, we have to find the derivative of both sides with respect to T using the power rule: $ v' = 10T^{-1/2}$
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