Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 15


The velocity decreases at a rate of $8$ x $10^{-5}\ cm/sec$.

Work Step by Step

$v = 6.4 * 10^{-8} - 0.001r^2$ To find the rate of change, we have to find the derivative f the function which we can do using the power rule: $v' = -0.002r$ Now we substitute r=0.004 into the equation to find the rate of change at that specific point: $v' = -0.002(0.004) = -0.00008$ To interpret this answer, we note that the number is negative and so the velocity decreases at a rate of $8$ x $10^{-5}\ cm/sec$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.