# Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 129: 1

10 square units per unit

#### Work Step by Step

First, we note that the equation for area of a square is: $$A = s^2$$ By taking the derivative of both sides we get: $$A' = 2s$$ When s = 5, the rate of change, or the derivative at that specific point is: $$A'(5) = 2(5) = 10\ square\ units\ per\ unit$$

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