## Calculus (3rd Edition)

The object is cooling or decreasing at a rate of $7.5^{\circ}/minute$.
$T(t) = \frac{3}{8}t^2 - 15t + 180$ To find the rate of change, first we need to find the derivative which we can do using the power rule: $T'(t) = \frac{3}{4}t - 15$ Now, we substitute t=10 into the equation at that specific point: $T'(10) = \frac{3}{4}*10 - 15 = 7.5 - 15 = -7.5$ To interpret this data, we note that the rate is negative which implies the temperature goes down or cools down. So the object is cooling or decreasing at a rate of $7.5^{\circ}/minute$.