## Calculus (3rd Edition)

First, we note that the equation for volume of a cube to be: $$V=s^3$$ By taking the derivative of both sides we get: $$V′=3s^2$$ When s = 5, the rate of change, or the derivative at that specific point is: $$V′(5)=3(5^2)=3(25) = 75\ square\ units\ per\ unit$$