## Calculus (3rd Edition)

$G(x)=(g(x))^{2}=g(x)\cdot g(x)$ Applying the product rule, we get $G'(x)=g'(x)\cdot g(x)+g(x)\cdot g'(x)=2(g(x)\cdot g'(x))$ $G'(4)=2(g(4)\cdot g'(4))=2(5\times-1)=-10$