## Calculus (3rd Edition)

$f’(x) = 1$
$f(x) = (x^{\frac{1}{2}}+1)(x^{\frac{1}{2}}-1);$ $x\geq 0$ Product and Power Rules: $f’(x) = \frac{1}{2}( x^{-\frac{1}{2}})(x^{\frac{1}{2}}-1) + \frac{1}{2}( x^{-\frac{1}{2}})(x^{\frac{1}{2}}+1)$ $f’(x) = \frac{1}{2} (1-x^{-\frac{1}{2}}) + \frac{1}{2}(1+ x^{-\frac{1}{2}})$ $f’(x) = \frac{1}{2} (1-x^{-\frac{1}{2}} + 1+ x^{-\frac{1}{2}})$ $f’(x) = \frac{1}{2} (2)$ $f’(x) = 1$