## Calculus (3rd Edition)

$f’(x) = 6x^5 +4x^3+18x^2 + 5$
$f(x) = (x^3 + x +1)(x^3+5)$ Product Rule: $f’(x) = (3x^2 +1)(x^3+5)+(3x^2)(x^3+x+1)$ $f’(x) = (3x^5 +15x^2 +x^3 +5+3x^5+3x^3 +3x^2)$ $f’(x) = 6x^5 +4x^3+18x^2 + 5$