Answer
$$\frac{d}{dx}((ax+b)(abx^2+1))=a(abx^2+1)+2abx(ax+b).$$
Work Step by Step
By using the product rule, we have
$$\frac{d}{dx}((ax+b)(abx^2+1))=a(abx^2+1)+2abx(ax+b).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 122: 36
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