Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Exercises - Page 122: 37


$$\frac{d}{dt} \left( \frac{xt-4}{t^2-x}\right) =\frac{-xt^2+8t-x^2}{(t^2-x)^2}.$$

Work Step by Step

By the quotient rule, we have $$\frac{d}{dt} \left( \frac{xt-4}{t^2-x}\right)=\frac{(t^2-x)(x )-(xt-4)(2t)}{(t^2-x)^2}\\ =\frac{-xt^2+8t-x^2}{(t^2-x)^2}.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.