## Calculus (3rd Edition)

$f(0)=2$
We are given the function: $f(x)=x\sin\dfrac{1}{x}+2$, $x\not=0$ Graph the function: The function is continuous on $(-\infty,0)$ and $(0,\infty)$. We notice that close to $x=0$ the function approaches $2$, therefore in order to make it continuous in $x=0$ we must take: $f(0)=2$