Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 67: 36

Answer

The domain of the function $$ f(x)=\sqrt{x^2+9}$$ is $ R $ and it is continuous.

Work Step by Step

Since $ x^2+9\geq 0$ for any value of $ x\in R $ and is a continuous polynomial, then the domain of the function $$ f(x)=\sqrt{x^2+9}$$ is $ R $ and it is continuous.
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