Calculus (3rd Edition)

The function has a discontinuity at $x=2$. Moreover, the discontinuity is infinite because $\lim\limits_{x \to 2}\frac{x+1}{4x-2}=\infty$ .
Since $$4x-2=0 \Longrightarrow x=2$$ then the function has a discontinuity at $x=2$. Moreover, the discontinuity is infinite because $\lim\limits_{x \to 2}\frac{x+1}{4x-2}=\infty$ .