## Calculus (3rd Edition)

The function $f(x)=\frac{1}{2^x-2^{-x}}$ is discontinuous at $x=0$. The discontinuity is infinite.
Since we have $$2^x-2^{-x}=0 \Longrightarrow 2^{2x}=2^0 \Longrightarrow x=0.$$ Hence, the function $f(x)=\frac{1}{2^x-2^{-x}}$ is discontinuous at $x=0$. The discontinuity is infinite.