Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.4 Limits and Continuity - Exercises - Page 67: 58



Work Step by Step

Since $f(x)$ is continuous, then it is continuous at $x=3$; thus,we use the property that $$f(3)=\lim_{x\to 3}f(x)$$ where $f(3)=-4(3)+c=-12+c$ and $\lim_{x\to 3}f(x)=2(3)+3=9$ Hence, we get $$9=-12+c\Longrightarrow c=21.$$ That is, $c=21$.
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