Answer
$div\left( {\bf{F}} \right) = 3{x^2}y + {y^2}$
$curl\left( {\bf{F}} \right) = \left( {2yz - 2xz} \right){\bf{i}} + \left( {{z^2} - {x^3}} \right){\bf{k}}$
Work Step by Step
We have ${\bf{F}} = \left( {{F_1},{F_2},{F_3}} \right) = \left( {{x^3}y,x{z^2},{y^2}z} \right)$.
1. $div\left( {\bf{F}} \right) = \frac{{\partial {F_1}}}{{\partial x}} + \frac{{\partial {F_2}}}{{\partial y}} + \frac{{\partial {F_3}}}{{\partial z}}$
$div\left( {\bf{F}} \right) = 3{x^2}y + {y^2}$
2. $curl\left( {\bf{F}} \right) = \left| {\begin{array}{*{20}{c}}
{\bf{i}}&{\bf{j}}&{\bf{k}}\\
{\frac{\partial }{{\partial x}}}&{\frac{\partial }{{\partial y}}}&{\frac{\partial }{{\partial z}}}\\
{{x^3}y}&{x{z^2}}&{{y^2}z}
\end{array}} \right|$
$curl\left( {\bf{F}} \right) = \left( {2yz - 2xz} \right){\bf{i}} + \left( {{z^2} - {x^3}} \right){\bf{k}}$