Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 17 - Line and Surface Integrals - 17.2 Line Integrals - Exercises - Page 935: 68

Answer

The conclusion (b) is correct.

Work Step by Step

Let $I = \mathop \smallint \limits_C^{} f\left( {x,y,z} \right){\rm{d}}s$. Since $f\left( {x,y,z} \right) \ge m$ for some number $m$ and all points $\left( {x,y,z} \right)$ on $C$, we have $I = \mathop \smallint \limits_C^{} f\left( {x,y,z} \right){\rm{d}}s \ge \mathop \smallint \limits_C^{} m{\rm{d}}s$ Since $m$ is constant, we get $I \ge m\mathop \smallint \limits_C^{} {\rm{d}}s$ Let $L$ be the length of $C$. Thus, $I \ge mL$. Therefore, the conclusion (b) is correct.
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