Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 28

Answer

$$ e_v =\left\langle\frac{1}{\sqrt{6}},\frac{1}{\sqrt{6}},\frac{2}{\sqrt{6}} \right\rangle.$$

Work Step by Step

$$ e_v=\frac{v}{\|v\|}=\frac{\langle1,1,2 \rangle }{\sqrt{1+1+4}}\\ =\left\langle\frac{1}{\sqrt{6}},\frac{1}{\sqrt{6}},\frac{2}{\sqrt{6}} \right\rangle.$$
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