Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 17


The vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are not equivalent.

Work Step by Step

First, we have $$\overrightarrow{ AB}=B-A=(3,3,5)-(1,1,0)=\langle 2,2,5 \rangle,$$ $$\overrightarrow{ PQ}=Q-P=(4,-7,13)-(2,-9,7)=\langle 2,2,6 \rangle.$$ Now, the vectors $\overrightarrow{ AB}$ and $\overrightarrow{ PQ}$ are not equivalent.
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