Answer
$$\langle16,-1,9 \rangle.$$
Work Step by Step
$$4\langle 6,-1,1 \rangle-2\langle1,0,-1 \rangle+3\langle-2,1,1\rangle\\
=\langle 24,-4,4 \rangle-\langle2,0,-2\rangle+\langle-6,3,3\rangle\\
=\langle16,-1,9 \rangle.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 23
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