Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 23


$$\langle16,-1,9 \rangle.$$

Work Step by Step

$$4\langle 6,-1,1 \rangle-2\langle1,0,-1 \rangle+3\langle-2,1,1\rangle\\ =\langle 24,-4,4 \rangle-\langle2,0,-2\rangle+\langle-6,3,3\rangle\\ =\langle16,-1,9 \rangle.$$
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