Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 659: 21


$$\langle-2,-2,3 \rangle.$$

Work Step by Step

$$\frac{1}{2}\langle 4,-2,8 \rangle-\frac{1}{3}\langle 12,3,3 \rangle=\langle 2,-1,4 \rangle-\langle 4,1,1 \rangle\\ =\langle-2,-2,3 \rangle.$$
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