#### Answer

Converges.

#### Work Step by Step

We have, the series
$$
\sum_{n=1}^{\infty}\left(\frac{1}{e^{0.02}}\right)^{n}
$$
Which is a geometric series with $r=\frac{1}{e^{0.02}}=0.98 \lt 1$ and hence it converges.

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

Converges.

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