## Calculus (3rd Edition)

$$|x-3|\leq5$$
Plug in (-2,8) for (a,b) in the equations for c $$c = (-2)+(8)\div2 = 3$$ Plug in answer for c into equation for r $$r =(8)-(3) = 5$$ Plug in answers for c and r into inequality equation $$|x(-3)|\leq(5)$$ Simplify $$|x-3|\leq5$$