## Calculus (3rd Edition)

$[-\frac{7}{4}, \frac{9}{4}]$
1. In order for the equation to be true, the equation between the absolute value brackets must be between -8 and 8. Redefine the equation to get rid of the absolute value brackets: $|4x-1| \leq 8$ $-8 \leq 4x-1 \leq 8$ 2. Solve each side of the equation $-8 \leq 4x-1$ $-7 \leq 4x$ (Add 1 to each side) $-\frac{7}{4} \leq x$ (Divide each side by 4) $4x-1 \leq 8$ $4x \leq 9$ (Add 1 to each side) $x \leq \frac{9}{4}$ (Divide each side by 4) 3. Since the original equation is said to be less than or equal ($\leq$) to 8, place your final answer in square brackets $[-\frac{7}{4}, \frac{9}{4}]$