## Calculus (3rd Edition)

4$\lt$x$\lt$20
1.) Set what the inequality equals to what it originally equals, and then set it to the opposite of that number with the opposite inequality sign x-12$\lt$8 and x-12$\gt$-8 2.) Solve the first inequality for x by adding 12 to both sides. x-12 $\lt$ 8 + 12 + 12 = x$\lt$ 20 3.)Solve the second equality for x by adding 12 to both sides. x-12$\gt$-8 + 12 + 12 = x$\gt$ 4 4.) Combine the two inequalities to solve for x 4$\lt$x$\lt$20