Answer
$|x+2| \leq 2$
Work Step by Step
1. x belongs to the set of points from -4 to 0, with square brackets indicating that they endpoints are included. This can be rewritten as:
$-4 \leq x \leq 0$
2. In order to express this in terms of an inequality, we must show that:
$|x−c| \leq r$
and $c−r \leq x \leq c+r$
3. By combining steps one and two:
$c−r=-4$, and $c+r=0$
4. In order to satisfy those equations:
$c=-2$, and $r=2$
Therefore:
$|x+2| \leq 2$
