## Calculus 10th Edition

Writing equation in slope intercept form: 3x + 4y = 7 y = -$\frac{3}{4}$x + $\frac{7}{4}$ So, slope of the line is -$\frac{3}{4}$ a) line parallel to 3x + 4y = 7 and passing through point (4, -5) (y + 5)/(x - 4) = -$\frac{3}{4}$ 3x + 4y = -8 3x +4y +8 = 0 b) line perpendicular to 3x + 4y = 7 and passing through point (4, -5) will have slope $\frac{4}{3}$ (y + 5)/(x - 4) = $\frac{4}{3}$ 4x - 3y = 31 4x -3y -31 = 0