Calculus 10th Edition

$0 = x + 2y - 5$
Given: Point: $(9, -2)$ x-intercept: $(2a,0)$ y-intercept: $(0,a)$ $a\ne0$ First find the standard form of the equation: Start by finding the slope: $m = \frac{0-a}{2a-0} = -\frac{a}{2a} = -\frac{1}{2}$ Point slope form equation using the given point: $(y - y_{1} = m(x -x_{1}))$ $y - (-2) = -\frac{1}{2}(x-9)$ Convert to standard: $(y =mx +b)$ $y = -\frac{1}{2}x + \frac{9}{2} -2$ $y = -\frac{1}{2}x + \frac{5}{2}$ Now convert to General form: $(0 = Ax + Bx + C)$ $2y = -x +5$ $x +2y - 5 = 0$