## Calculus 10th Edition

$x + y - 3 = 0$
1. First we will find the slope of line using two intercepts (0,a) and (a, 0) m = ($y_{2}$ - $y_{1}$)/($x_{2}$ - $x_{1}$) m = (0 - a) / (a - 0) m = -1 2. Now, again using the same equation and given point on line ( 1,2), we will find the value of a ($y_{2}$ - $y_{1}$)/($x_{2}$ - $x_{1}$) = m (2-a)/ (1- 0) = -1 a = 3 3. So, equation of line will be: $\frac{x}{3}$ + $\frac{x}{3}$ = 1 3x + 3y = 9 3x +3y -9 = 0 x + y - 3 = 0