Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - P.2 - Linear Models and Rates of Change - Exercises: 48

Answer

$\frac{x}{a}+\frac{y}{b}=1$

Work Step by Step

let $(a,0)$ $(x_{1},y_{1})$ let $(0,b)$ $(x_{2},y_{2})$ Use the formula $\frac{y-y_{1}}{y_{2}-y_{1}}=\frac{x-x_{1}}{x_{2}-x_{1}}$ $\frac{y-0}{b-0}=\frac{x-a}{0-a}$ $\frac{y}{b}=\frac{-(x-a)}{a}$ $\frac{y}{b}=-\frac{x}{a}+\frac{a}{a}$ $\frac{y}{b}=-\frac{x}{a}+1$ Therefore, $\frac{x}{a}+\frac{y}{b}=1$
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