## Calculus 10th Edition

y = $-\frac{8}{3}x$ + $\frac{40}{3}$
First find the slope using the two given points. To find the slope use the slope definition. m = $\frac{8-0}{2-5}$ = $-\frac{8}{3}$ Use the point slope form equation of the line to find the equation of the line. Note that you can plug in either point on the point-slope-form equation. y - 0 = $-\frac{8}{3}$(x-5) Simplify: y = $-\frac{8}{3}x$ + $\frac{40}{3}$