Answer
Matches $(d)$
Work Step by Step
Given $$f(x)= x+1, \ g(x)=(x-1)^2$$
To determine the area between the curves $f(x)= x+1, \ g(x)=(x-1)^2$
first we get the intersection points, by solving the following equations
$y= x+1, \ y=(x-1)^2$
we get $(0,1),(3,4)$
So,
\begin{align}
A&=\int_ 0^3 (x+1-(x-1)^2) \ dx \\
&=\left[\frac{x^2}{2}+x-\frac{(x-1)^3}{3}\right]_0^3\\
&=4.5\approx 4
\end{align}